Regex That Wil Match After Keyword And Before Question Mark

I'm getting stuck on regex101 with the following test string: https://localhost:8443/site/recipes/recepten-zoeken/menugang:hoofdgerecht/soort:italiaans/seizoen:winter?Nrpp=24 I'm t

Solution 1:

Try capturing your values in a capturing group:

recepten-zoeken\/([^?]+)\?

Explanation

• recepten-zoeken Match literally
• \/ Match forward slash
• ([^?]+) Capture in a group a negated character class [^ which will match NOT a question mark. (This will contain your value)
• \? Match literally

var s = "https://localhost:8443/site/recipes/recepten-zoeken/menugang:hoofdgerecht/soort:italiaans/seizoen:winter?Nrpp=24"console.log(s.match(/recepten-zoeken\/([^?]+)\?/)[1])

Credits to ctwheels for providing the snippet and comment.

Solution 2:

Use capturing group.(() brackets indicates capturing group)

Capture upto last question mark

Try this regex \/recepten-zoeken\/(.*)\?

Explanation:-

• \/ Match forward slash
• recepten-zoeken Match literally
• \/ Match forward slash
• (.*) Capture in a group all value(except new line) upto last question mark in string(This will contain your value)
• \? Match literally

//-------------------------select upto last ? -----------------------------

str = "https://localhost:8443/site/recipes/recepten-zoeken/menugang:hoofdgerecht/soort:italiaans/seizoen:winter?Nrpp=24";
var myRegexp = /\/recepten-zoeken\/(.*)\?/;
console.log(myRegexp.exec(str)[1]);

Capture upto first question mark

Try this regex \/recepten-zoeken\/([^?]*)\?.

Explanation:-

• \/ Match forward slash
• recepten-zoeken Match literally
• \/ Match forward slash
• ([^?]*) Capture in a group all value(except ?) upto first question mark in string(This will contain your value)(here [^?] means match any character except ?)
• \? Match literally

//-------------------------select upto first ? -----------------------------var str = "https://localhost:8443/site/recipes/recepten-zoeken/menugang:hoofdgerecht/soort:italiaans/seizoen?:winter?Nrpp=24";
var myRegexp = /\/recepten-zoeken\/([^?]*)\?/;
console.log(myRegexp.exec(str)[1]);

Solution 3:

This would do it:

var match = url.match(/\/recepten-zoeken\/([^?]+)\?/);
// match[1] == "menugang:hoofdgerecht/soort:italiaans/seizoen:winter"

This regex will match the first occurrence of /recepten-zoeken/, then it will start capturing all characters that are not question marks ([^?] is a negative character class which matches anything not in the class).

Note that it will also ensure that there is a question mark. If you want to support cases where there is no question mark, then just remove the final \?.

Your original regular expression only matches a single character (the .), then it tries to look ahead for characters that are not c, e, k, / or between n and z.