Filtering An Array Of Objects With Multiple Filter Conditions

Lets assume I have an array of objects: let users = [{ name: 'Mark', location: 'US', job: 'engineer' }, { name: 'Mark', location: 'US', job: 'clerk' }, { name: 'Angela', lo

Solution 1:

Use Object.entries() on filters to get an array of [key, values] pairs. Iterate the pairs with Array.every(), and check that each pair includes the value of the current object.

constfn = (arr, filters) => {
  const filtersArr = Object.entries(filters)
  
  return arr.filter(o => 
    filtersArr.every(([key, values]) => 
      values.includes(o[key])
    )
  )
}

const users = [{"name":"Mark","location":"US","job":"engineer"},{"name":"Mark","location":"US","job":"clerk"},{"name":"Angela","location":"Europe","job":"pilot"},{"name":"Matthew","location":"US","job":"engineer"}]

const filters = {
  name: ["Mark", "Matthew"],
  location: ["US"],
  job: ["engineer"]
}

const result = fn(users, filters)

console.log(result)

One caveat of using Array.includes() is that differences in case would provide a false answer (Engineer and engineer in this case). To solve that convert the current word to a RegExp, with the Case-insensitive search flag (i), and check using Array.some() if it fits any of the words in the array.

constfn = (arr, filters) => {
  const filtersArr = Object.entries(filters)
  
  return arr.filter(o => 
    filtersArr.every(([key, values]) => {
      const pattern = newRegExp(`^${o[key]}$`, 'i')
    
      return values.some(v => pattern.test(v))
    })    
  )
}

const users = [{"name":"Mark","location":"US","job":"engineer"},{"name":"Mark","location":"US","job":"clerk"},{"name":"Angela","location":"Europe","job":"pilot"},{"name":"Matthew","location":"US","job":"engineer"}]

const filters = {
  name: ["Mark", "Matthew"],
  location: ["US"],
  job: ["Engineer"]
}

const result = fn(users, filters)

console.log(result)

Solution 2:

You can loop over the entries of the filters object and ensure that the value of each key is one of the allowed ones.

let users = [{name:"Mark",location:"US",job:"Engineer"},{name:"Mark",location:"US",job:"clerk"},{name:"Angela",location:"Europe",job:"pilot"},{name:"Matthew",location:"US",job:"Engineer"}];
const filters = {
  name: ["Mark", "Matthew"],
  location: ["US"],
  job: ["Engineer"]
};
const res = users.filter(o =>Object.entries(filters).every(([k,v])=>v.includes(o[k])));
console.log(res);