Capture Four Numbers With One Javascript Regular Expression

December 21, 2023 Post a Comment

I want to capture four groups with only one regex. I have this piece of text: PAY VALUES TO SUM - WITHOU NOTHING: 0.00 (IGNORE THE REST) PAY VALUES TO SUM - ADD. 50 YEARS: 0.00 (IG

Solution 1:

You simply need to capture a double number like 0.00, this is the Regex (\d.\d{2}) you need:

var text = 'PAY VALUES TO SUM - WITHOUT NOTHING: 0.13 13º WORD WORD: 0.00';
text += 'PAY VALUES TO SUM - ADD. 50 YEARS: 3.85 WORD WORD WORD: 0.00';
text += 'PAY VALUES TO SUM - ADD. 70 YEARS: 9.02 WORD WORD WORD: 0.00';
text += 'PAY VALUES TO SUM - ADD. 80 YEARS: 5.21 WORD WORD WORD WORD WORD WORD WORD: 0.00';

var re = /(\d.\d{2})/g;

var m;
 
while ((m = re.exec(text)) !== null) {
    if (m.index === re.lastIndex) {
        re.lastIndex++;
    }
    document.write(m[0]+" ");
}

And this is a regex101 DEMO.

Note: I used document.write() only for test, avoid using it.

EDIT:

This is the new Regex (PAY VALUES TO SUM - (?:WITHOU NOTHING|ADD. \d{2} YEARS): (\d.\d{2})) of the second attempt to get what you need, I hope it is what you are looking for:

var text = 'PAY VALUES TO SUM - WITHOU NOTHING: 0.13 13º WORD WORD: 0.00';
text += 'PAY VALUES TO SUM - ADD. 50 YEARS: 3.85 WORD WORD WORD: 0.00';
text += 'PAY VALUES TO SUM - ADD. 70 YEARS: 9.02 WORD WORD WORD: 0.00';
text += 'PAY VALUES TO SUM - ADD. 80 YEARS: 5.21 WORD WORD WORD WORD WORD WORD WORD: 0.00';

var re = /(PAY VALUES TO SUM - (?:WITHOU NOTHING|ADD. \d{2} YEARS): (\d.\d{2}))/g;

var m;

while ((m = re.exec(text)) !== null) {
  if (m.index === re.lastIndex) {
    re.lastIndex++;
  }
  document.write(m[0] + "<br>");
}

Solution 2:

Start by putting your keys into an array:

var keys = [
  'PAY VALUES TO SUM - WITHOU NOTHING:','PAY VALUES TO SUM - ADD. 50 YEARS:','PAY VALUES TO SUM - ADD. 70 YEARS:','PAY VALUES TO SUM - ADD. 80 YEARS:'
];

Now compile a regular expression that looks for a number after each key. You can use [0-9.]+ to match a sequence of one or more characters in the class [0-9.], which consists of the digits 0 through 9 and the . (period). That will suffice to match numbers that look like 0.00 and 314.159.

Here is a regular expression that uses [0-9.]+ to extract a number after each key:

var regex = RegExp(keys[0] + '\\s+([0-9.]+).*?' +
                   keys[1] + '\\s+([0-9.]+).*?' +
                   keys[2] + '\\s+([0-9.]+).*?' +
                   keys[3] + '\\s+([0-9.]+).*?', 'gi');

Note that \\s+ matches one or more spaces after each key. You can change it to \\s* if you want to match zero or more spaces.

We are using .*? to match the shortest possible sequence of characters before the next key. The 'gi' flags make the regular expression match globally (g) and without regard to case (i).

Before executing the regular expression, it's a good idea to replace all invisible whitespace with visible spaces. That's because .* does not match line-ending characters.

Baca Juga

text = text.replace(/\s/g, ' ');

The snippet below demonstrates this approach with the sample text and keys that you gave in your question.

functionprint(s) {
  document.write(s + '<br />');
}

var keys = [
  'PAY VALUES TO SUM - WITHOU NOTHING:',
  'PAY VALUES TO SUM - ADD. 50 YEARS:',
  'PAY VALUES TO SUM - ADD. 70 YEARS:',
  'PAY VALUES TO SUM - ADD. 80 YEARS:'
];

// Compile a regular expression that looks for a number after each key.var regex = RegExp(keys[0] + '\\s+([0-9.]+).*?' +
                   keys[1] + '\\s+([0-9.]+).*?' +
                   keys[2] + '\\s+([0-9.]+).*?' +
                   keys[3] + '\\s+([0-9.]+).*?', 'gi');

var text = document.getElementById('content').innerHTML;

// Replace newlines and other invisible whitespace with visible spaces.
text = text.replace(/\s/g, ' ');

// Find and display all matches.var count = 0;
while (true) {
  var match = regex.exec(text);
  if (match === null) {
    break;
  }
  ++count;
  print('match ' + count + ': ' +
        [match[1], match[2], match[3], match[4]].join(' '));
}

body {
  font-family: sans-serif;
}
#content {
  display: none;
}

<divid="content">
PAY VALUES TO SUM - WITHOU NOTHING: 0.00 13º WORD WORD: 0.00
PAY VALUES TO SUM - ADD. 50 YEARS: 0.00 WORD WORD WORD: 0.00
PAY VALUES TO SUM - ADD. 70 YEARS: 0.00 WORD WORD WORD: 0.00
PAY VALUES TO SUM - ADD. 80 YEARS: 0.00 WORD WORD WORD WORD WORD WORD WORD: 0.00
</div>

Solution 3:

If I understood correctly, you only need the 1st occurrence of each xx.xx number after the : in each line, as numbers can occur also after the 1st occurence.

If that is the case, then this is your regular expression:

/^.*?:\s*([\d\.]+).*/gm

And this is a demo: https://regex101.com/r/gT9tJ0/1

Solution 4:

Try this: you can use this short regex :/PAY\s+VALUES\s+TO\s+SUM\s+[^:]+:\s*([\d.]+)/gmi

Regex demo

var re = /PAY\s+VALUES\s+TO\s+SUM\s+[^:]+:\s*([\d.]+)/gmi; 
    var str = 'var text = \'PAY VALUES TO SUM - WITHOU NOTHING: 0.00 13º WORD WORD: 0.00\' +\ntext += \'PAY VALUES TO SUM - ADD. 50 YEARS: 0.00 WORD WORD WORD: 0.00\';\ntext += \'PAY VALUES TO SUM - ADD. 70 YEARS: 0.00 WORD WORD WORD: 0.00\';\ntext += \'PAY VALUES TO SUM - ADD. 80 YEARS: 0.00 WORD WORD WORD WORD WORD WORD WORD: 0.00\';\n';
    var m;
     
    while ((m = re.exec(str)) !== null) {
        if (m.index === re.lastIndex) {
            re.lastIndex++;
        }
        // View your result using the m-variable.document.write(m[1]+ ' ');
    }

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