Sort Javascript Array Of Objects By Two Properties And Given Order

I have this JavaScript array of Objects: data = [ {'deviation': 57.41, 'provider': 'This', 'measure': 'median'}, {'deviation': 49.02, 'provider': 'All', 'measure': 'median'

Solution 1:

It sounds like you are doing:

data.sort(function(a, b) {
    //sort by provider
});

data.sort(function(a, b) {
    //sort by measure
});

But what you want to do is:

data.sort(function(a, b) {
    //sort by provider, but if they are equal, sort by measure
});

So something like

data.sort(function(a, b) {
    if (a.provider === b.provider) {
        return a.measure.localeCompare(b.measure);
    }
    return b.provider.localeCompare(a.provider);
});

Solution 2:

You could chain the sorting criteria with logical OR ||.

For a set of strings with a defined order, you could use an object for getting the wanted order.

{
    first_quartile:1,
    median:2,
    third_quartile:3
}

This lets you sort some item, if not in the order list ssort to start with default zero or to bottom with a huge value like Infinity.

In this case the pattern looks like

(order[a.measure] || 0) - (order[a.measure] || 0)                // to top
(order[a.measure] || Infinify ) - (order[a.measure] || Infinity) // to bottom

var array = [{ deviation: 57.41, provider: "This", measure: "median" }, { deviation: 49.02, provider: "All", measure: "median" }, { deviation: 199.67, provider: "This", measure: "third_quartile" }, { deviation: 152.31, provider: "All", measure: "third_quartile" }, { deviation: 41.48, provider: "This", measure: "first_quartile" }, { deviation: -1.07, provider: "All", measure: "first_quartile" }],
   order = { first_quartile: 1, median: 2, third_quartile: 3 };

array.sort(function (a, b) {
    return b.provider.localeCompare(a.provider) || order[a.measure] - order[b.measure];
});

console.log(array);

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