Find All Instances Of 'old' In A Webpage And Replace Each With 'new', Using A Javascript Bookmarklet

What I want to do is replace all instances of 'old' in a webpage with 'new' in a JS bookmarklet or a greasemonkey script. How can I do this? I suppose jQuery or other frameworks ar

Solution 1:

A function that is clobber-proof. That mean's this won't touch any tags or attributes, only text.

function htmlreplace(a, b, element) {    
    if (!element) element = document.body;    
    var nodes = element.childNodes;
    for (var n=0; n<nodes.length; n++) {
        if (nodes[n].nodeType == Node.TEXT_NODE) {
            var r = new RegExp(a, 'gi');
            nodes[n].textContent = nodes[n].textContent.replace(r, b);
        } else {
            htmlreplace(a, b, nodes[n]);
        }
    }
}

htmlreplace('a', 'r');

Bookmarklet version:

javascript:function htmlreplace(a,b,element){if(!element)element=document.body;var nodes=element.childNodes;for(var n=0;n<nodes.length;n++){if(nodes[n].nodeType==Node.TEXT_NODE){nodes[n].textContent=nodes[n].textContent.replace(new RegExp(a,'gi'),b);}else{htmlreplace(a,b,nodes[n]);}}}htmlreplace('old','new');

Solution 2:

If you replace the innerHtml then you will destroy any dom events you have on the page. Try traversing the document to replace text:

function newTheOlds(node) {
    node = node || document.body;
    if(node.nodeType == 3) {
        // Text node
        node.nodeValue = node.nodeValue.split('old').join('new');
    } else {
        var nodes = node.childNodes;
        if(nodes) {
            var i = nodes.length;
            while(i--) newTheOlds(nodes[i]);
        }
    }
}

newTheOlds();

The split/join is faster than doing "replace" if you do not need pattern matching. If you need pattern matching then use "replace" and a regex:

node.nodeValue = node.nodeValue.replace(/(?:dog|cat)(s?)/, 'buffalo$1');

As a bookmarklet:

javascript:function newTheOlds(node){node=node||document.body;if(node.nodeType==3){node.nodeValue=node.nodeValue.split('old').join('new');}else{var nodes=node.childNodes;if(nodes){var i=nodes.length;while(i--)newTheOlds(nodes[i]);}}}newTheOlds();

Solution 3:

For older browsers will need to change Node.TEXT_NODE to 3 and the node.textContent to node.nodeValue; so final function should read:

function htmlreplace(a, b, element) {    
    if (!element) element = document.body;    
    var nodes = element.childNodes;
    for (var n=0; n<nodes.length; n++) {
        if (nodes[n].nodeType == 3) { //Node.TEXT_NODE == 3
            var r = new RegExp(a, 'gi');
            nodes[n].nodeValue = nodes[n].nodeValue.replace(r, b);
        } else {
            htmlreplace(a, b, nodes[n]);
        }
    }
}

Solution 4:

A simple line that works along jQuery:

`javascript:var a = function(){$("body").html($("body").html().replace(/old/g,'new'));return;}; a();`

Without jQuery:

`javascript:function a (){document.body.innerHTML=document.body.innerHTML.replace(/old/g, "new" );return;}; a();`

The function returning nothing is very important, so the browser is not redirected anywhere after executing the bookmarklet.

Solution 5:

Yet another recursive approach:

function replaceText(oldText, newText, node){ 
  node = node || document.body; 

  var childs = node.childNodes, i = 0;

  while(node = childs[i]){ 
    if (node.nodeType == Node.TEXT_NODE){ 
      node.textContent = node.textContent.replace(oldText, newText); 
    } else { 
      replaceText(oldText, newText, node); 
    } 
    i++; 
  } 
}

Minified bookmarklet:

javascript:function replaceText(ot,nt,n){n=n||document.body;var cs=n.childNodes,i=0;while(n=cs[i]){if(n.nodeType==Node.TEXT_NODE){n.textContent=n.textContent.replace(ot,nt);}else{replaceText(ot,nt,n);};i++;}};replaceText('old','new');